If p(a) = 0.62, p(b) = 0.47, and p(a ∪ b) = 0.88, then p(a ∩ b) =

Solution:

Given,

P(a) = 0.62

P(b) = 0.47

P(a ∪ b) = 0.88

We have to find P(a ∩ b).

For mutually non-exclusive events, we know the probability formula as

P(a∩b) = P(a) + P(b) - P(a ∪ b)

= 0.62 + 0.47 - 0.88

= 1.09 - 0.88

= 0.21

Therefore, the value of P(a ∩ b) = 0.21

If p(a) = 0.62, p(b) = 0.47, and p(a ∪ b) = 0.88, then p(a ∩ b) =

Summary:

If p(a) = 0.62, p(b) = 0.47, and p(a ∪ b) = 0.88, then p(a ∩ b) = 0.21