If the quadratic formula is used to solve 2x(x + 5) = 4, what are the solutions?

Solution:

The standard form of a quadratic equation is ax² + bx + c = 0

The formula to find the roots are

x = [-b ± √b² - 4ac]/ 2a

The given equation is

2x (x + 5) = 4

Using the distributive property

2x² + 10x - 4 = 0

Here a = 2, b = 10 and c = -4

Substituting it in the formula

x = [-10 ± √10² - 4(2)(-4)]/ 2(2)

By further calculation

x = [-10 ± √100 + 32]/ 4

x = [-10 ± √132]/ 4

Therefore, the solutions are [-10 + √132]/ 4 and [-10 - √132]/ 4.

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If the quadratic formula is used to solve 2x(x + 5) = 4, what are the solutions?

Summary:

If the quadratic formula is used to solve 2x(x + 5) = 4, the solutions are [-10 + √132]/ 4 and [-10 - √132]/ 4.