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# Solve for \(b_{2}\) in A = 1/2h (\(b_{1}\) +_{ }\(b_{2}\)), if A = 16, h = 4, and \(b_{1}\) = 3

Let us change the subject of the equation and solve for \(b_{2}\)

## Answer: The value of \(b_{2}\)_{ }= 5

**Explanation:**

We need to change the subject of the equation to \(b_{2}\)

A = 1/2 h(\(b_{1}\) +_{ }\(b_{2}\))

Substituting A = 16 ; h = 4 ; \(b_{1}\) = 3

16 = 4/2 (3 + \(b_{2}\))

16 = 2(3 + \(b_{2}\))

8 = (3 + \(b_{2}\))

5 = \(b_{2}\)

### Hence, solving for \(b_{2}\)_{ }in A = 1/2h (\(b_{1}\) +\(b_{2}\)), when A = 16, h = 4, and \(b_{1}\) = 3, gives \(b_{2}\)_{ }= 5

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