# Solve for b_{2} in A = 1/2h (b_{1}+b_{2}), if A = 16, h = 4, and b_{1} = 3

Let us change the subject of the equation and solve for b_{2}

## Answer: Solving for b_{2 }in A = 1/2h (b_{1}+b_{2}), when A = 16, h = 4, and b_{1} = 3 gives b_{2 }= 5

**Explanation:**

We need to change the subject of the equation to b_{2}

A = 1/2 h(b_{1} +b_{2})

Substituting A = 16 ; h = 4 ; b_{1} = 3

16 = 4/2 (3 +b_{2})

16 = 2(3 +b_{2})

8 = (3+b_{2})

5 = b_{2}

### Hence, Solving for b_{2 }in A = 1/2h (b_{1}+b_{2}), when A = 16, h = 4, and b_{1} = 3 gives b_{2 }= 5