What is the equation of the line that passes through the points (-1,3) and (1,11)?

Solution:

The point-slope form of an equation is

y - y₁ = m (x - x₁)

Where m is the slope

(x1, y1) is a point on the line

The slope can be found using the formula

m = (y₂ - y₁)/ (x₂ - x₁)

Where (x₁, y₁) and (x₂, y₂) are the coordinate points

(-1,3) and (1,11) are the two given points

m = (11 - 3) / (1 + 1)

m = 8/2

m = 4

By using m = 4 and (x₁, y₁) = (1, 11)

y - 11 = 4 (x - 1)

By further calculation

y - 11 = 4x - 4

y = 4x - 4 + 11

y = 4x + 7

Therefore, the equation of the line is y = 4x + 7.

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What is the equation of the line that passes through the points (-1,3) and (1,11)?

Summary:

The equation of the line that passes through the points (-1,3) and (1,11) is y = 4x + 7.