# A verandah of width 2.25 m is constructed all along outside a room which is 5.5 m long and 4 m wide. Find:

(i) the area of the verandah

(ii) the cost of cementing the floor of the verandah at the rate of ₹ 200 per m^{2}

**Solution:**

Let's represent the situation diagrammatically as shown below.

Let the blue region represent the room and the yellow region represent the verandah.

Area of the room = Length × Breadth

= 5.5 m × 4 m

= 22 m^{2}

Length of the room including veranda = 5.5 m + (2.25 × 2) m

= 5.5 m + 4.5 m

= 10 m

Breadth of the room including veranda = 4 m + (2.25 × 2) m

= 4 m + 4.5 m

= 8.5 m

Area of the room including veranda = Length × Breadth

= 10 m × 8.5 m

= 85 m^{2}

(i) Area of the veranda = Area of the room including veranda - Area of the room

= 85 cm^{2} - 22 cm^{2}

= 63 m^{2}

(ii) The cost of cementing 1 m^{2} floor of the veranda = Rs.200

The cost of cementing 63 m^{2} floor of the veranda = Rs.200 × 63

= Rs.12600

**Video Solution:**

## A verandah of width 2.25 m is constructed all along outside a room which is 5.5 m long and 4 m wide. Find: (i) the area of the verandah. (ii) the cost of cementing the floor of the verandah at the rate of ₹ 200 per m².

### Maths NCERT Solutions Class 7 - Chapter 11 Exercise 11.4 Question 4

**Summary:**

A verandah of width 2.25 m is constructed all along outside a room which is 5.5 m long and 4 m wide. Then: (i) the area of the verandah is 63 m^{2}. (ii) the cost of cementing the floor of the verandah at the rate of ₹ 200 per m^{2} is ₹12600.