# Architects design many types of buildings. They draw plans for houses, such as the plan shown in Fig. 9.68: An architect wants to install decorative moulding around the ceilings in all the rooms. The decorative moulding costs ₹500/metre. Find how much moulding will be needed for family room

**Solution:**

The figure represents the plan for a house.

An architect wants to install decorative moulding around the ceilings in all the rooms.

The decorative moulding costs ₹500/metre.

We have to find the moulding needed for the family room.

From the plan we observe that the family room is in rectangular shape.

__Perimeter of rectangle__ = 2(length + breadth)

Length = 4.57 m

Breadth = 5.48 m

Perimeter = 2(4.57 + 5.48)

= 2(10.05)

= 20.10 m

Therefore, the moulding needed for the family room is 20.10 m.

**✦ Try This: **If it costs Rs.320 to carpet a square room 8 metres broad, what would it cost, at the same rate per square metre, to carpet an oblong room 6 metres by 5 metres?

**☛ Also Check: **NCERT Solutions for Class 7 Maths Chapter 11

**NCERT Exemplar Class 7 Maths Chapter 9 Problem 126 (a) (i)**

## Architects design many types of buildings. They draw plans for houses, such as the plan shown in Fig. 9.68: An architect wants to install decorative moulding around the ceilings in all the rooms. The decorative moulding costs ₹500/metre. Find how much moulding will be needed for family room

**Summary:**

Architects design many types of buildings. They draw plans for houses, such as the plan shown in Fig. 9.68: An architect wants to install decorative moulding around the ceilings in all the rooms. The decorative moulding costs ₹500/metre. 20.10 m of moulding will be needed for the family room.

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