# Draw a triangle ABC in which BC = 6 cm, CA = 5 cm and AB = 4 cm. Construct a triangle similar to it and of scale factor 5/3

**Solution:**

Steps of Construction

1. Construct a __line segment__ BC = 6cm

2. With S and C as centres, construct two arcs of radii 4 cm and 5 cm which intersect with each other at A.

3. Let us join BA and CA. ∆ABC is the required __triangle__.

4. From the point B, construct a ray BX downwards which makes an __acute angle__

5. Now mark 5 points B_{1}, B_{2}, B_{3}, B_{4}, B_{5} on BX where

BB_{1} = B_{1}B_{2} = B_{2}B_{3} = B_{3}B_{4} = B_{4}B_{5}

6. Join B_{3}C and from the point B_{5} construct B_{5}M || B_{3}C which intersects the extended line segment BC at M

7. From the point M construct MN || CA which intersects BA at N

8. Triangle NBM is the required triangle.

Therefore, ∆NBM is the required triangle.

**✦ Try This: **Draw a triangle ABC in which BC = 4 cm, CA = 5 cm and AB = 6 cm. Construct a triangle similar to it and of scale factor 7/5.

**☛ Also Check:** NCERT Solutions for Class 10 Maths Chapter 11

**NCERT Exemplar Class 10 Maths Exercise 10.3 Problem 3**

## Draw a triangle ABC in which BC = 6 cm, CA = 5 cm and AB = 4 cm. Construct a triangle similar to it and of scale factor 5/3

**Summary:**

A triangle ABC in which BC = 6 cm, CA = 5 cm and AB = 4 cm is drawn. A triangle similar to it and of scale factor 5/3 is constructed

**☛ Related Questions:**

- Construct a tangent to a circle of radius 4 cm from a point which is at a distance of 6 cm from its . . . .
- Given a rhombus ABCD in which AB = 4 cm and ∠ABC = 60°, divide it into two triangles say, ABC and AD . . . .
- Two line segments AB and AC include an angle of 60° where AB = 5 cm and AC = 7 cm. Locate points P a . . . .

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