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# Find the product by suitable rearrangement:

(a) 2 × 1768 × 50 (b) 4 × 166 × 25 (c) 8 × 291 × 125

(d) 625 × 279 × 16 (e) 285 × 5 × 60 (f) 125 × 40 × 8 × 25

**Solution:**

We will be using the associative property of multiplication to find the product of the numbers given below.

(a) 2 × 1768 × 50

= 2 × 50 × 1768

= 100 × 1768

= 176800

(b) 4 × 166 × 25

= 4 × 25 × 166

= 100 × 166

= 16600

(c) 8 × 291 × 125

= 8 × 125 × 291

= 1000 × 291

= 291000

(d) 625 × 279 × 16

= 625 × 16 × 279

= 10000 × 279

= 2790000

(e) 285 × 5 × 60

= 285 × 300

= 85500

(f) 125 × 40 × 8 × 25

= 125 × 8 × 40 × 25

= 1000 × 1000

= 1000000

Class 6 Maths NCERT Solutions Chapter 2 Exercise 2.2 Question 2

## Find the product by suitable rearrangement: (a) 2 × 1768 × 50 (b) 4 × 166 × 25 (c) 8 × 291 × 125 (d) 625 × 279 × 16 (e) 285 × 5 × 60 (f) 125 × 40 × 8 × 25

**Summary:**

The product by suitable rearrangement for 2 × 1768 × 50, 4 × 166 × 25, 8 × 291 × 125, 625 × 279 × 16, 285 × 5 × 60 and 125 × 40 × 8 × 25 are 176800, 16600, 291000, 2790000, 85500 and 1000000 respectively.

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