# Find the sum of n terms in the G.P. x^{3}, x^{5}, x^{7}, ..... (if x ≠ ± 1)

**Solution:**

The given G.P is

x^{3}, x^{5}, x^{7}, .....

Here, a = x^{3} and r = x^{2}

It is known that

S_{n} = a (1 - r^{n})/(1 - r)

Therefore,

S_{n} = x^{3} (1 - (x^{2})^{n})/(1 - x^{2})

= x^{3} (1 - x^{2n})/(1 - x^{2})

NCERT Solutions Class 11 Maths Chapter 9 Exercise 9.3 Question 10

## Find the sum of n terms in the G.P. x^{3}, x^{5}, x^{7}, ..... (if x ≠ ± 1)

**Summary:**

We had to find the sum of n terms in the G.P x^{3}, x^{5}, x^{7}, .... Since we know that S_{n} = a (1 - r^{n})/(1 - r) the sum comes out to be x^{3} (1 - x^{2n})/(1 - x^{2})

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