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# Find using distributive property:

(a) 728 × 101 (b) 5437 × 1001 (c) 824 × 25

(d) 4275 × 125 (e) 504 × 35

**Solution:**

We will be using the distributive property to solve this.

According to the distributive property,

a × (b + c) = a × b + a × c

(a) 728 × 101

101 can be written as 100 + 1

728 × 101

= 728 × (100 + 1)

= 728 × 100 + 728 × 1 [using distrbutive property]

= 72800 + 728

= 73528

(b) 5437 × 1001

1001 can be written as 1000 +1

= 5437 × (1000 + 1)

= 5437 × 1000 + 5437 × 1 [using distrbutive property]

= 5437000 + 5437

= 5442437

(c) 824 × 25

= 824 × (20 + 5)

= (824 × 20) + (824 × 5) [using distrbutive property]

= 16480 + 4120

= 20600

(d) 4275 × 125

= 4275 × (100 + 20 + 5)

= 4275 × 100 + 4275 × 20 + 4275 × 5 [using distrbutive property]

= 427500 + 85500 + 21375

= 534375

(e) 504 × 35

= (500 + 4) × 35

= 500 × 35 + 4 × 35 [using distrbutive property]

= 17500 + 140

= 17640

NCERT Solutions for Class 6 Maths Chapter 2 Exercise 2.3 Question 4

## Find using distributive property: (a) 728 × 101 (b) 5437 × 1001 (c) 824 × 25 (d) 4275 × 125 (e) 504 × 35

**Summary:**

Using distributive property, the values of 728 × 101, 5437 × 1001, 824 × 25, 4275 × 125 and 504 × 35 are 73528, 5442437, 20600, 534375 and 17640 respectively.

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