How many 3-digit even numbers can be made using the digits 1, 2, 3, 4, 6, 7, if no digit is repeated?

Solution:

We have to find the number of 3-digit even numbers that can be made using the digits 1, 2, 3, 4, 6, 7, if no digit is repeated.

The total number of digits available = 6 (which are 1, 2, 3, 4, 6, 7).
For the number to be even the last digit must be 2, 4, or 6.
So no. of ways of choosing last digit = 3
As no digit should be repeated,
No. of ways of choosing first digit = 5 
No. of ways of choosing second digit = 4

Using the fundamental principle of counting,
Total possible number of ways = 3×5×4 = 60

NCERT Solutions Class 11 Maths Chapter 7 Exercise 7.3 Question 3

How many 3-digit even numbers can be made using the digits 1, 2, 3, 4, 6, 7, if no digit is repeated?

Summary:

The number of 3-digit even numbers that can be made using the digits 1, 2, 3, 4, 6, 7, if no digit is repeated is 60