If S and T are two sets such that S has 21 elements, T has 32 elements, and S ∩ T has 11 elements, how many elements does S ∪ T have?
Solution:
It is given that S and T are two sets such that:
n (S) = 21, n (T) = 32 and n (S ∩ T) = 11
We know that n(S υ T) is,
n (S υ T) = n (S) + n (T) - n (S ∩ T)
= 21 + 32 - 11
= 53 - 11
= 42
Therefore, S υ T has 42 elements.
NCERT Solutions Class 11 Maths Chapter 1 Exercise 1.6 Question 4
If S and T are two sets such that S has 21 elements, T has 32 elements, and S ∩ T has 11 elements; how many elements does S υ T have?
Summary:
It is given that S and T are two sets such that S has 21 elements, T has 32 elements, and S ∩ T has 11 elements. We have found that S υ T has 42 elements.
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