# Passing through the points (-1, 1) and (2, -4)

**Solution:**

It is known that the equation of the line passes through points (x_{1}, y_{1}) and (x_{2}, y_{2}) is

y - y_{1} = [(y2 - y1 / (x_{2} - x_{1}] ( x - x_{1})

Therefore, the equation of the line passing through the points (- 1, 1) and (2, - 4) is

( y - 1) = [(- 4 - 1)/(2 + 1)] ( x + 1)

( y - 1) = (- 5/3) ( x + 1)

3( y - 1) = - 5( x + 1)

3y - 3 = - 5x - 5

5x + 3y + 2 = 0

Hence, the equation of the line is 5x + 3y + 2 = 0

NCERT Solutions Class 11 Maths Chapter 10 Exercise 10.2 Question 7

## Passing through the points (-1, 1) and (2, -4)

**Summary:**

The equation of the line passing through the points (-1, 1) and (2, -4) is 5x + 3y + 2 = 0