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# PQRS is a parallelogram (Fig 11.23). QM is the height from Q to SR and QN is the height from Q to PS. If SR = 12 cm and QM = 7.6 cm. Find:

(a) the area of the parallelogram PQRS

(b) QN, if PS = 8 cm

**Solution:**

(a) SR = 12 cm and QM = 7.6 cm.

Area of parallelogram PQRS = Base × Height

= SR × QM

= 12 cm × 7.6 cm

= 91.2 cm^{2}

(b) Base = PS = 8 cm

Area of the parallelogram = 91.2 cm^{2} [calculated in part (a)]

Area of parallelogram PQRS = Base × Height

91.2 cm^{2 }= 8 cm × QN

QN = 91.2 cm^{2 }/ 8 cm

QN = 11.4 cm

**☛ Check: **NCERT Solutions for Class 7 Maths Chapter 11

**Video Solution:**

## PQRS is a parallelogram (Fig 11.23). QM is the height from Q to SR and QN is the height from Q to PS. If SR = 12 cm and QM = 7.6 cm. Find: (a) the area of the parallelogram PQRS (b) QN, if PS = 8 cm

Class 7 Maths NCERT Solutions Chapter 11 Exercise 11.2 Question 5

**Summary:**

PQRS is a parallelogram. QM is the height of Q to SR and QN is the height from Q to PS. If SR = 12 cm and QM = 7.6 cm. Then: (a) The area of the parallelogram PQRS is 91.2 cm^{2 }(b) QN is 22.8 cm, if PS = 8 cm

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