Show that the function given by f (x) = 3x + 17 is strictly increasing on R

Solution:

Increasing functions are those functions that increase monotonically within a particular domain,

and decreasing functions are those which decrease monotonically within a particular domain.

Given that:

f (x) = 3x + 17

Let x₁ and x₂ be any two numbers in R.

Then,

x₁ < x₂

⇒ 3x₁ + 17 < 3x₂ + 17

= f (x₁) < f (x₂)

Thus, f is strictly increasing on R

NCERT Solutions Class 12 Maths - Chapter 6 Exercise 6.2 Question 1

Show that the function given by f (x) = 3x + 17 is strictly increasing on R

Summary:

Hence we have concluded that the function is given by f (x) = 3x + 17 is strictly increasing on R