# The base of an isosceles triangle is 4/3 cm. The perimeter of the triangle is \(4{\Large\frac{2}{15}}\)cm. What is the length of either of the remaining equal sides?

**Solution:**

We know that,

In an isosceles triangle, two sides of the triangle are equal.

The perimeter of a triangle = Sum of the lengths of all three sides

Let's form a linear equation for the given problem statement.

Base of an isosceles triangle = 4/3 cm

Let the equal sides measure as x cm each

Therefore, Perimeter of the triangle = x + x + 4/3 = \(4{\Large\frac{2}{15}}\)

Solving the above equation

⇒ 2x + 4/3 = \(4{\Large\frac{2}{15}}\)

⇒ 2x = 62/15 - 4/3

⇒ 2x = 42/15

⇒ x = 21/15

⇒ x = 7/5

Therefore, the length of the remaining equal sides of the triangle is 7/5 cm

**☛ Check: **Class 8 Maths NCERT Solutions Chapter 2

**Video Solution:**

## The base of an isosceles triangle is 4/3 cm. The perimeter of the triangle is \(4{\Large\frac{2}{15}}\) cm. What is the length of either of the remaining equal sides?

NCERT Solutions Class 8 Maths Chapter 2 Exercise 2.2 Question 3

**Summary:**

Given that the base of an isosceles triangle is 4/3 cm and its perimeter is \(4{\Large\frac{2}{15}}\)cm, the remaining equal sides are equal to 7/5 cm each.

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