The distribution below gives the weights of 30 students of a class. Find the median weight of the students
We know that,
Median = l + [(n/2 - cf)/f] × h
- Class size, h
- Number of observations, n
- Lower limit of median class, l
- Frequency of median class, f
- Cumulative frequency of class preceding median class, cf
n = 30 ⇒ n/2 = 15
From the table, it can be observed that cumulative frequency (cf) just greater than 15 is 19, belonging to class 55 - 60.
Therefore, median class = 55 - 60
Class size, h = 5
Lower limit of median class, l = 55
Frequency of median class, f = 6
Cumulative frequency of class preceding median class, cf = 13
Median = l +[ (n/2 - cf)/f] × h
= 55 + [(15 - 13)/6] × 5
= 55 + (2/6) × 5
= 55 + 5/3
= 55 + 1.67
Therefore, median weight is 56.67 kg.
The distribution below gives the weights of 30 students of a class. Find the median weight of the students.
NCERT Solutions for Class 10 Maths Chapter 14 Exercise 14.3 Question 7
The distribution below gives the weights of 30 students of a class. The median weight of the students is 56.67 kg.
☛ Related Questions:
- The following frequency distribution gives the monthly consumption of electricity of 68 consumers of a locality. Find the median, mean and mode of the data and compare them.
- If the median of the distribution given below is 28.5, find the values of x and y.
- A life insurance agent found the following data for distribution of ages of 100 policy holders. Calculate the median age, if policies are given only to persons having age 18 years onwards but less than 60 year.
- The lengths of 40 leaves of a plant are measured correct to the nearest millimetre, and the data obtained is represented in the following table: Find the median length of the leaves. (Hint: The data needs to be converted to continuous classes for finding the median, since the formula assumes continuous classes. The classes then change to 117.5 - 126.5, 126.5 - 135.5, . . ., 171.5 - 180.5.).