A basketball team has 9 players in how many different ways can the coach select 2 players?

Solution:

Since the problem is about selecting two players it is the problem of combinations.

As the basketball team comprises 9 distinct players and two have to be selected, means there will be a finite number of selections.

The number of different ways x number of basket players can be selected from n players is given by the formula:

\(^n{C_x}\) = n!/(x!(n-x)!) 

\(^9{C_2}\) = 9!/(2!7!)In the given problem n = 9 and x = 2 (two players at a time). Therefore the number of selections which are possible are:

\(^9{C_2}\) = 9!/(2!7!) = (9 × 8 × 7!)/(2! × 7!) = 36 ways

A basketball team has 9 players in how many different ways can the coach select 2 players?

Summary:

A basketball team has 9 players and there the coach can therefore select 2 players from 9 players in 36 ways.