A cyclist travels a distance of 1 km in the first hour, 0.5 km in the second hour and 0.3 km in the third hour. What is the average speed in km/hr and m/sec?
Time, speed, and distance are related using the equation: Distance = Speed × Time.
Answers: The average speed of the cyclist who travels a distance of 1 km in the first hour, 0.5 km in the second hour and 0.3 km in the third hour is 0.6 km/hr or 1/6 m/s.
To find the average speed we need to use the relation:
Average speed = Total distance traveled/ Total time taken
Let's now consider the conditions given in the question to find the required value.
Let's find the total distance traveled and the total time taken.
The total distance travelled = 1 km + 0.5 km + 0.3 km = 1.8 km.
Total time taken = 1 hr + 1 hr + 1 hr = 3 hr
Now, Average speed = Total distance traveled/ Total time taken
or, Average speed = 1.8/3 = 0.6 km/hr
Now let's convert km/hr to m/sec
Since we know 1 km = 1000 m and 1 hr = (60 × 60) s = 3600 s
Therefore, 1 km/hr = 1000m/3600s
So 0.6 km/hr = 0.6 × 1000/3600 m/s
= (0.6 × 1000)/3600 m/s
= 600/3600 m/s
= 1/6 m/s