# A cyclist travels a distance of 1 km in the first hour, 0.5 km in the second hour and 0.3 km in the third hour. What is the average speed in km/hr and m/sec?

Time, speed, and distance are related using the equation: **Distance = Speed × Time.**

## Answers: The average speed of the cyclist who travels a distance of 1 km in the first hour, 0.5 km in the second hour and 0.3 km in the third hour is 0.6 km/hr or 1/6 m/s.

To find the average speed we need to use the relation:

**Average speed = Total distance traveled/ Total time taken**

Let's now consider the conditions given in the question to find the required value.

**Explanation:**

Let's find the total distance traveled and the total time taken.

The total distance travelled = 1 km + 0.5 km + 0.3 km = 1.8 km.

Total time taken = 1 hr + 1 hr + 1 hr = 3 hr

Now, Average speed = Total distance traveled/ Total time taken

or, Average speed = 1.8/3 = 0.6 km/hr

Now let's convert km/hr to m/sec

Since we know 1 km = 1000 m and 1 hr = (60 × 60) s = 3600 s

Therefore, 1 km/hr = 1000m/3600s

So 0.6 km/hr = 0.6 × 1000/3600 m/s

= (0.6 × 1000)/3600 m/s

= 600/3600 m/s

= 1/6 m/s