Approximate the real number solution(s) to the polynomial function f(x) = x³ - 4x² + x + 6.
x = -3, x = -1, x = 2
x = 3, x = 1, x = -2
x = 3, x = -1, x = 2
x = -3, x = 1, x = -2

Solution:

The given polynomial function is
f(x) = x³ - 4x² + x + 6

Consider x = 3, x = -1 and x = 2

So we get

f(3) = 3³ - 4(3)² + 3 + 6

f(3) = 27 - 36 + 3 + 6

f(3) = 0

f(-1) = (-1)³ - 4(-1)² + (-1) + 6

f(-1) = -1 - 4 - 1 + 6

f(-1) = 0

f(2) = 2³ - 4(2)² + 2 + 6

f(2) = 8 - 16 + 2 + 6

f(2) = 0

Therefore, the real number solutions are x = 3, x = -1 and x = 2.

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Approximate the real number solution(s) to the polynomial function f(x) = x³ - 4x² + x + 6.
x = -3, x = -1, x = 2
x = 3, x = 1, x = -2
x = 3, x = -1, x = 2
x = -3, x = 1, x = -2

Summary:

The real number solution(s) to the polynomial function f(x) = x³ - 4x² + x + 6 are x = 3, x = -1 and x = 2.