# Determine the standard form of the equation of the line that passes through (0, 5) and (4,0).

**Solution:**

The standard equation of a line is Ax + By + C = 0.

Equation of the line in two-point form is (y - y_{1}) = [(y_{2} - y_{1})/(x_{2} - x_{1})] (x - x_{1}) ------(1)

Given that line passes through (0, 5) and (4, 0)

∴ Substituting (x_{1}, y_{1}) = (0, 5) and (x_{2}, y_{2}) = (4, 0) in equation (1),

(y - y_{1}) = [(y_{2} - y_{1}) / (x_{2} - x_{1})] (x - x_{1})

(y - 5) = [(0 - 5)/ (4 - 0)] [x - 0]

(y - 5) = (-5 / 4) x

4y - 20 = -5x

5x + 4y - 20 = 0

This is the required equation of line which is in general form.

## Determine the standard form of the equation of the line that passes through (0, 5) and (4,0).

**Summary:**

The standard form of the equation of the line that passes through (0, 5) and (4,0) is 5x + 4y - 20 = 0.

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