Find 3 consecutive even numbers such that the sum of the first and last numbers exceed the second number by 10.
An even number is a number that is a multiple of 2.
Answer: The 3 Consecutive even numbers such that the sum of first and last numbers exceed the second number by 10 are 8,10 and 12
Let's find those 3 consecutive even numbers.
Let the three consecutive even numbers be x, (x + 2) and (x + 4)
According to the question,
First number + Last number = Second number + 10
x + x + 4 = x + 2 + 10
2x + 4 = x + 12
2x - x = 12 - 4
x = 8
Thus, the numbers are x = 8,
x + 2 = 10 and
x + 4 = 12