Find cot θ if csc θ = sqrt 5/2 and tan θ > 0
Solution:
Given, cosec θ = sqrt(5/2) , we have cot θ = sqrt(cosec² θ - 1)
= sqrt{(5/2)² - 1) = sqrt( 21/4)
Now cot θ = sqrt(21/4)
Example: Find sin θ and cos θ if tan θ = 3/4
Given that, tan θ = 3/4, we have sec θ = sqrt(1 +tan²θ)
⇒ sec θ = sqrt{1 + (3/4)²} = sqrt(25/16) = 5/4
∴ cos θ = 1 / sec θ = 1/ (5/4) = 4/5
sin θ = sqrt ( 1 - cos² θ) = sqrt{ 1 - (4/5)²} = sqrt(9/25) = 3/ 5
Find cot θ if csc θ = sqrt 5/2 and tan θ > 0
Summary:
The value of cot θ if csc θ = sqrt 5/2 and tan θ > 0 is sqrt(21/4)
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