Find the dimensions of a rectangle with a perimeter 60m whose area is as large as possible.

Solution:

It is given that

Perimeter of the rectangle  = 60m

Area of rectangle is as large as possible if both the values are the same number.

In order to have a maximum area in a rectangle, the dimensions should be equal.

Consider the dimensions as x

So perimeter can be written as

2 (x + x) = 60

2 (2x) = 60

By further calculation

4x = 60

Divide both sides by 4

x = 15

Therefore, the dimensions of a rectangle is 15m × 15m.

Find the dimensions of a rectangle with a perimeter 60m whose area is as large as possible.

Summary:

The dimensions of a rectangle with a perimeter 60m whose area is as large as possible is 15m × 15m.