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# How many possible values can be created with only 3 bits?

**Solution:**

The highest decimal value that can be represented by an unsigned n-bit binary word is 2^{n} - 1.

Using 'n' bits 2^{n} values can be created

Therefore, using 3 bits we will have 2^{3} = 8 values

The 8 values in binary and decimal form are as follows:

Binary form |
Decimal Form |
---|---|

000 | 0 |

001 | 1 |

010 | 2 |

011 | 3 |

100 | 4 |

101 | 5 |

110 | 6 |

111 | 7 |

Thus, the 8 values represent from 0 to 7 where 0 and 7 are included.

Therefore, a total of 8 values can be created using 3 bits, which are 0 to 7 where 0 and 7 are included.

## How many possible values can be created with only 3 bits?

**Summary:**

A total of 8 values can be created using 3 bits, which are 0 to 7 where 0 and 7 are included.

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