# Identify the radius of the circle whose equation is (x - 2)^{2} + (y - 8)^{2} = 16.

**Solution:**

Given: (x - 2)^{2} + (y - 8)^{2} = 16

The equation of a circle with center (h, k) and radius (r) is given by,

(x − h)^{2} + (y − k)^{2} = r^{2} ---------------- (1)

(x - 2)^{2} + (y - 8)^{2} = (4)^{2} -------------- (2)

Comparing the values of h, k and r in (1) and (2) we get,

Center (h, k) = (2, 8)

Radius (r) = 4

r = ± 4

Since radius means length, it cannot be negative.

Hence, the radius of the circle is 4

## Identify the radius of the circle whose equation is (x - 2)^{2 }+ (y - 8)^{2} = 16.

**Summary:**

The radius of the circle whose equation is (x - 2)^{2} + (y - 8)^{2} = 16 is 4.

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