# Identify the Radius of the Circle whose Equation is (x - 2)^{2} + (y - 8)^{2} = 16.

The standard equation of a circle is given by (x − h)^{2} + (y − k)^{2} = r^{2}

## Answer: The Radius of the Circle whose Equation is (x - 2)^{2} + (y - 8)^{2} = 16 is 4.

Let's solve it step by step.

**Explanation:**

Given: (x - 2)^{2} + (y - 8)^{2} = 16

The equation of a circle with center (h, k) and radius (r) is given by,

(x − h)^{2} + (y − k)^{2} = r^{2} ---------------- (1)

(x - 2)^{2} + (y - 8)^{2} = (4)^{2} -------------- (2)

Comparing the values of h, k and r in (1) and (2) we get,

Center (h, k) = (2, 8)

Radius (r) = 4

You can use the Equation of Circle Calculator to verify the answer.