# In a purse there are ₹20 notes, ₹10 notes and ₹50 notes. The number of ₹50 notes exceeds two times the ₹10 notes by 1. The number of ₹20 notes are 5 less than the number of ₹10 notes. If the total value of money in the purse is ₹860, find the number of each variety of notes.

We'll form an equation by assuming the numbers of each variety of notes.

## Answer: The number of ₹10 notes is 7, the Number of ₹20 notes is 2, and the number of ₹50 notes is 15.

Let's find the number of each variety of notes.

**Explanation: **

Let the number of ₹10 notes be x, therefore the total value of ₹10 notes would be ₹10x

The number of ₹20 notes would be (x - 5), therefore the total value of ₹20 notes would be ₹20(x - 5)

The number of ₹50 notes would be (2x + 1), therefore the total value of ₹50 notes would be ₹50(2x + 1)

Since the total value of the money in the purse is ₹860

10x + 20(x - 5) + 50(2x + 1) = 860

10x + 20x - 100 + 100x + 50 = 860

130x - 50 = 860

130x = 860 + 50

130x = 910

x = 7

Therefore, the number of each variety of notes will be:

Number of ₹10 notes = x = 7

Number of ₹20 notes = x - 5 = 7 - 5 = 2

Number of ₹50 notes = 2x + 1 = 2 × 7 + 1 = 14 + 1 = 15

### Thus, Number of ₹10 notes are 7, Number of ₹20 notes are 2 and number of ₹50 notes are 15.

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