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A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
Let f(x) = x+8 and g(x)=x2-6x-7, what is f(g(2))?
Solution:
g(x) = y\(_1\) = x2 - 6x - 7 ….. (1)
f(x) = y\(_2\) = x + 8 ….. (2)
f(g(x)) is a composite function that can be written as (fog)(x), where in the output values of g(x) are taken as its input values.
Where x is present in f(x) you should substitute y\(_1\)
I.e., substituting equation (1) in x which is present in equation (2)
f(g(x)) = y\(_1\) + 8 where y1 = x2 - 6x - 7
f(g(x)) = x2 - 6x - 7 + 8
f(g(x)) = x2 - 6x + 1
Now substitute x = 2 in f (g(x))
f(g(2)) = (2)2 - 6(2) + 1
So we get
f(g(2)) = 4 - 12 + 1
f(g(-1)) = 5 - 12 = - 7
Therefore, f(g(x)) when x = 2 is - 7.
Let f(x) = x+8 and g(x)=x2-6x-7, what is f(g(2))?
Summary:
Let f(x) = x+8 and g(x)=x2-6x-7, f(g(2)) is - 7.
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