To solve 493x = 3432x + 1, write each side of the equation in terms of base.

Solution:

Given, 493x = 3432x + 1

Grouping of common terms,

493x - 3432x = 1

-2939x = 1

Dividing both sides by -2939 to get the value of x.

x = 1/(-2939)

x = -0.00034025

x = -3.4025×10^-4

Therefore, writing the equation in terms of base, the value of x is -3.4025×10^-4.

Example:

To solve 123x = 1542x + 2, write each side of the equation in terms of base.

Solution:

Given, 123x = 1542x + 2

Grouping of common terms,

123x - 1542x = 2

-1419x = 2

Dividing both sides by -1419 to get the value of x.

x = 2/(-1419)

x = -0.00140944

x = -1.409×10^-3

Therefore, writing the equation in terms of base, the value of x is = -1.409×10^-3.

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To solve 493x = 3432x + 1, write each side of the equation in terms of base.

Summary:

To solve 493x = 3432x + 1, write each side of the equation in terms of base. The value of x is -3.4025×10^-4.