What is the area of the rectangle wxyz with vertices w(0, 1), x(3, 4), y(-1, 8), z(-4, 5) to the nearest unit

Solution:

Given vertices of the rectangle w(0, 1), x(3, 4), y(-1, 8), z(-4, 5)

We know that the area of the rectangle is given as follows:

Area of rectangle = length × width (product of the two adjacent sides)

Let us use the distance formula to find the length and the width of the rectangle.

Length of wx = √((3 - 0)² + (4 - 1)²)

= √(3² + 3²)

= √(18)

= 4.24

Length of xy = √((-1 - 3)² + (8 - 4)²)

= √((-4)² + 4²)

= √(32)

= 5.66

Area of rectangle= 4.24 × 5.66 = 24 square units.

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What is the area of the rectangle wxyz with vertices w(0, 1), x(3, 4), y(-1, 8), z(-4, 5) to the nearest unit

Summary:

The area of the rectangle wxyz with vertices w(0, 1), x(3, 4), y(-1, 8), z(-4, 5) to the nearest unit is 24 square units.