# What is the equation in point-slope form of the line passing through (-3, -4) and (0, 2)?

**Solution:**

Point slope form is used to represent a straight line using its slope and a point on the line. That means, the equation of a line whose slope is 'm' and which passes through a point (x_{1}, y_{1}) is found using the point slope form.

The slope of a line is the change in y-coordinate with respect to the change in x-coordinate of that line.

The equation of the slope is y_{2} - y_{1} = m (x_{2} - x_{1})

Where m is the slope of the line

The points given are (-3, -4) and (0, 2)

To find the slope,

m = (y_{2} - y_{1})/ (x_{2} - x_{1})

Substituting the values, we get

m = (2 + 4)/ (0 + 3)

m = 6/3

⇒ m = 2

The equation of a line is y = ax + b

To find the real equation, we have to use one point (0, 2)

2 = a(0) + b

Where a is the slope of the equation

2 = 0 + b

⇒ b = 2

We know, y = ax + b

Substituting the values, we get

y = 2x + 2

Therefore, the equation in point-slope form of the line is y = 2x + 2.

## What is the equation in point-slope form of the line passing through (-3, -4) and (0, 2)?

**Summary:**

The equation in point-slope form of the line passing through (-3, -4) and (0, 2) is y = 2x + 2.

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