What is the sum of the geometric sequence 3, 15, 75, … if there are 7 terms?
Solution:
The sum of the first n terms of a geometric sequence is given by the expression:
Sn = a(rn - 1)/r - 1
Where
Sn = Sum of the first n terms of the Geometric Ratio
a = First Term of the geometric series
r = common ratio of the geometric series
For the series given in the problem statement
a = 3, r = 5
And S7 = sum of first 7 terms
S7 = 3(57 - 1)/5 - 1
= 3(78125 - 1)/4
= 3(78124)/4
= 3(19531)
= 58593
What is the sum of the geometric sequence 3, 15, 75, … if there are 7 terms?
Summary:
The sum of the geometric sequence 3, 15, 75, … if there are 7 terms is 58593.
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