# What is the value of b^{2} - 4ac for the following equation 5x^{2} + 7x = 6?

A quadratic equation is in the form of ax^{2} + bx + = 0.

## Answer: The value of b^{2} - 4ac that satisfies the equation 5x^{2} + 7x = 6 is 169.

Let's find the value of b^{2} - 4ac.

**Explanation:**

A discriminant of a quadratic equation is a function of the coefficients of the polynomials.

D = b^{2} - 4ac

As per the question, the equation can be written as 5x^{2} + 7x - 6 = 0

a = coefficient of x^{2}, b = coefficient of x and c = constant term.

⇒ D = (7)^{2} - [4 × 5 × (-6)]

= 49 - 4 × ( - 30)

= 49 - (- 120 )

= 169