When any natural number is divided by 10, what is the sum of all possible remainders?
Solution:
Natural numbers are the part of the number system that includes all positive integers from 1 up to infinity.
Let's take some examples to see the possible remainders.
When 20 is divided by 10, the remainder is 0
When 21 is divided by 10, the remainder is 1
When 22 is divided by 10, the remainder is 2
Similarly, When 29 is divided by 10, the remainder is 9
Thus, we see that if every natural number is divided by 10, the possible remainders are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9
Sum of all possible remainders = 0 + 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 = 45
Therefore, when any natural number is divided by 10, sum of all possible remainders is 45.
When any natural number is divided by 10, what is the sum of all possible remainders?
Summary:
When any natural number is divided by 10, the sum of all possible remainders is 45.
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