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# Which is a zero of the quadratic function f(x) = 9x^{2} - 54x - 19?

x = 1/3, x = 3 1/3, x = 6 1/3, x = 9 1/3

**Solution:**

Given, f(x) = 9x^{2} - 54x - 19

We have to find zero of the quadratic function.

On solving,

f(x) = 9x^{2} - 54x - 19

= 9x^{2} - 57x - 3x - 19

= 3x(3x - 19) + 1(3x - 19)

= (3x + 1)(3x - 19)

Now, 3x + 1 = 0

⇒ 3x = -1

⇒ x = -1/3

3x - 19 = 0

⇒ 3x = 19

⇒ x = 19/3

⇒ x = 6 1/3

Therefore, the zeros of the function are x = -1/3 and x = 19/3.

## Which is a zero of the quadratic function f(x) = 9x^{2} - 54x - 19?

**Summary:**

The zeros of the quadratic function f(x) = 9x^{2} - 54x - 19 are x = -1/3 and x = 19/3.

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