# Write an equation of the line containing the point ( 4, 3) and parallel to the line having slope 4.

We will use the concept of the point-slope form of a straight line to find the equation.

## Answer: The equation in slope-intercept form of the line through the point P(4, 3) and parallel to the line having slope 4 is given as y = 4x - 13.

Let us see how we will use the concept of the point-slope form of the straight line to find the equation.

**Explanation:**

We will use the definition of slope to find the slope

Let us consider another point on the line that is (x, y).

We know that given two points (x_{1},y_{1}) and (x_{2},y_{2}) the slope is given by,

Slope(m) = (y_{2} - y_{1}) / (x_{2} - x_{1})

Hence, the slope of the line passing through the points (4, 3) and (x, y) is,

Slope = (y - 3) / (x - 4) = 4 [Since, slope = 4 (given)]

⇒ y - 3 = 4 (x - 4)

⇒ y = 4x - 16 + 3

⇒ y = 4x - 13