Arrange in descending order : 2²⁺³, (2²)³, 2 × 2², 3⁵/3², 3² × 3⁰, 2³ × 5²
Solution:
Given,2²⁺³, (2²)³, 2 × 2², 3⁵/3², 3² × 3⁰, 2³ × 5²
We have to arrange the number in descending order.
Descending(decreasing) order is the arrangement of the given numbers from the largest to the smallest.
2²⁺³ = 2⁵ = 2 × 2 × 2 × 2 × 2 = 32
(2²)³ = 2⁶ = 2 × 2 × 2 × 2 × 2 × 2 = 64
2 × 2² = 2¹⁺² = 2³ = 2 × 2 × 2 = 8
3⁵/3² = 3⁵⁻² = 3³ = 3 × 3 × 3 = 27
3² × 3⁰ = 3²⁺⁰ =3² = 3 × 3 = 9
2³ × 5² = 2 × 2 × 2 × 5 × 5 = 200
8 < 9 < 27 < 32 < 64 < 200
Therefore, the descending order:
2³ × 5² ＞(2²)³ ＞2²⁺³ ＞3⁵/3²＞3² × 3⁰＞2 × 2²
✦ Try This: Arrange in descending order: 3²⁺³, (5²)³, 3 × 2², 4⁵/5², 2² × 2⁰, 3³ × 6²
☛ Also Check: NCERT Solutions for Class 7 Maths Chapter 13
NCERT Exemplar Class 7 Maths Chapter 11 Problem 67
Arrange in descending order: 2²⁺³, (2²)³, 2 × 2², 3⁵/3², 3² × 3⁰, 2³ × 5²
Summary:
Descending order: 2³ × 5² ＞(2²)³ ＞2²⁺³ ＞3⁵/3²＞3² × 3⁰＞2 × 2²
☛ Related Questions:
visual curriculum