# Arrange in descending order : 2²⁺³, (2²)³, 2 × 2², 3⁵/3², 3² × 3⁰, 2³ × 5²

**Solution:**

Given,2²⁺³, (2²)³, 2 × 2², 3⁵/3², 3² × 3⁰, 2³ × 5²

We have to arrange the number in __descending order__.

Descending(decreasing) order is the arrangement of the given __numbers__ from the largest to the smallest.

2²⁺³ = 2⁵ = 2 × 2 × 2 × 2 × 2 = 32

(2²)³ = 2⁶ = 2 × 2 × 2 × 2 × 2 × 2 = 64

2 × 2² = 2¹⁺² = 2³ = 2 × 2 × 2 = 8

3⁵/3² = 3⁵⁻² = 3³ = 3 × 3 × 3 = 27

3² × 3⁰ = 3²⁺⁰ =3² = 3 × 3 = 9

2³ × 5² = 2 × 2 × 2 × 5 × 5 = 200

8 < 9 < 27 < 32 < 64 < 200

Therefore, the descending order:

2³ × 5² ＞(2²)³ ＞2²⁺³ ＞3⁵/3²＞3² × 3⁰＞2 × 2²

**✦ Try This: **Arrange in descending order: 3²⁺³, (5²)³, 3 × 2², 4⁵/5², 2² × 2⁰, 3³ × 6²

**☛ Also Check: **NCERT Solutions for Class 7 Maths Chapter 13

**NCERT Exemplar Class 7 Maths Chapter 11 Problem 67**

## Arrange in descending order: 2²⁺³, (2²)³, 2 × 2², 3⁵/3², 3² × 3⁰, 2³ × 5²

**Summary:**

Descending order: 2³ × 5² ＞(2²)³ ＞2²⁺³ ＞3⁵/3²＞3² × 3⁰＞2 × 2²

**☛ Related Questions:**

visual curriculum