# Carry out the following divisions

(i) 28x^{4 }÷ 56x (ii) -36 y^{3 }÷ 9 y^{2 }(iii) 66 pq^{2}r^{3 }÷ 11qr^{2}

(iv) 34x^{3}y^{3}z^{3 }÷ 51xy^{2} z^{3 }(v) 12a^{8}b^{8 }÷ (-6a^{6}b^{4} )

**Solution:**

We will be finding out factors of the expressions and then cancel out common factors of the numerator and the denominator.

(i) 28x^{4 }÷ 56x

28x^{4} can be written as 2 × 2 × 7 × x × x × x × x and

56x can be written as 2 × 2 × 2 × 7 × x

Then, 28x^{4} ÷ 56x = (2 × 2 × 7 × x × x × x × x) / (2 × 2 × 2 × 7 × x)

= x^{3}/2

(ii) - 36y^{3 }÷ 9y^{2}

-36y^{3} can be written as and - 2 × 2 × 3 × 3 × y × y × y and

9y^{2} can be written as 3 × 3 × y × y

Then, -36y^{3} ÷ 9y^{2} = (-2 × 2 × 3 × 3 × y × y × y) / (3 × 3 × y × y)

= -4y

(iii) 66 pq^{2}r^{3 }÷ 11qr^{2}

66pq^{2}r^{3} can be written as 2 × 3 × 11 × p × q × q × r × r × r and

11qr^{2} can be written as 11 × q × r × r

Then, 66 pq^{2}r^{3} ÷ 11qr^{2} = (2 × 3 × 11 × p × q × q × r × r × r) / (11 × q × r × r)

= 6pqr

(iv) 34x^{3}y^{3}z^{3 }÷ 51xy^{2}z^{3}

34x^{3}y^{3}z^{3} can be written as 2 × 17 × x × x × x × y × y × y × z × z × z and

51xy^{2}z^{3} can be written as 3 × 17 × x × y × y × z × z × z

Then, 34x^{3}y^{3}z^{3} ÷ 51xy^{2}z^{3 }= (2 × 17 × x × x × x × y × y × y × z × z × z) /(3 × 17 × x × y × y × z × z × z)

= 2x^{2}y / 3

(v) 12a^{8}b^{8} ÷ (-6a^{6}b^{4})

12a^{8}b^{8} can be written as 2 × 2 × 3 × a^{8} × b^{8 }and

-6a^{6}b^{4} can be written as -2 × 3 × a^{6} × b^{4}

Then, 12a^{8}b^{8} ÷ (-6a^{6}b^{4}) = (2 × 2 × 3 × a^{8} × b^{8}) / (-2 × 3 × a^{6} × b^{4})

= -2a^{2}b^{4}

**☛ Check: **NCERT Solutions for Class 8 Maths Chapter 14

**Video Solution:**

## Carry out the following divisions. (i) 28x⁴^{ }÷ 56x (ii) -36 y³^{ }÷ 9 y²^{ }(iii) 66 pq²r³^{ }÷ 11qr²^{ }(iv) 34x³y³z³^{ }÷ 51xy² z³^{ }(v) 12a⁸b⁸^{ }÷ (-6a⁶b⁴ )

Class 8 Maths NCERT Solutions Chapter 14 Exercise 14.3 Question 1

**Summary:**

The following divisions are carried out (i) 28x^{4 }÷ 56x (ii) -36 y^{3 }÷ 9 y^{2 }(iii) 66 pq^{2}r^{3 }÷ 11qr^{2 }(iv) 34x^{3}y^{3}z^{3 }÷ 51xy^{2} z^{3 }(v) 12a^{8}b^{8 }÷ (-6a^{6}b^{4} ) and the result is as follows (i)x^{3}/2 (ii) -4y (iii) 6pqr (iv) 2x^{2}y / 3 (v) -2a^{2}b^{4}

**☛ Related Questions:**

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