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# Divide ₹10000 in two parts so that the simple interest on the first part for 4 years at 12 percent per annum may be equal to the simple interest on the second part for 4.5 years at 16 percent per annum.

**Solution:**

Given, ₹10000 is divided in two parts

The simple interest on the first part for 4 years at 12% per annum may be equal to the simple interest on the second part for 4.5 years at 16% per annum.

We have to find the two parts.

Let the first part be x and the second part be 10000 - x.

We know, I = P × R × T/100

According to the question,

x × 12 × 4 / 100 = (10000 - x) × 16 × 4.5 /100

x × 12 × 4 = (10000 - x) × 16 × 4.5

48x = (10000 - x) × 16 × 4.5

48x = (10000 - x) × 72

48x = 10000(72) - 72x

48x + 72x = 720000

120x = 720000

12x = 72000

x = 72000/12

x = ₹6000

Second part = 10000 - 6000 = ₹4000

Therefore, the first part is ₹6000 and the second part is ₹4000.

**✦ Try This: **What sum of money, lent at simple interest will amount to Rs. 735.94 in 3 years, when the rate of interest is 8%?

**☛ Also Check: **NCERT Solutions for Class 7 Maths Chapter 8

**NCERT Exemplar Class 7 Maths Chapter 7 Problem 131**

## Divide ₹10000 in two parts so that the simple interest on the first part for 4 years at 12 percent per annum may be equal to the simple interest on the second part for 4.5 years at 16 percent per annum.

**Summary:**

On dividing ₹10000 in two parts so that the simple interest on the first part for 4 years at 12 percent per annum may be equal to the simple interest on the second part for 4.5 years at 16 percent per annum we get the first part as ₹6000 and the second part as ₹4000.

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