Find the coordinates of the foci, the vertices, the length of major axis, the minor axis, the eccentricity and the length of the latus rectum of the ellipse x2/25 + y2/100 = 1
Solution:
The given equation is x2/25 + y2/100 = 1
Here, the denominator of y/100 is greater than the denominator of x/25
Therefore, the major axis is along the y-axis, while the minor axis is along the x-axis.
On comparing the given equation with
x2/ b2 + y2/a2 = 1 we obtain b = 5 and a = 10
Hence,
c = √a² - b²
= √100 - 25
= √75
= 5√3
Therefore,
The coordinates of the foci are (0, ± 5√3)
The coordinates of the vertices are (0, ± 10)
Length of major axis = 2a = 20
Length of minor axis = 2b = 10
Eccentricity, e = c/a = 5√3/10
Length of latus rectum = 2b2/a = (2 × 25)/10 = 5
NCERT Solutions Class 11 Maths Chapter 11 Exercise 11.3 Question 4
Find the coordinates of the foci, the vertices, the length of major axis, the minor axis, the eccentricity and the length of the latus rectum of the ellipse x2/25 + y2/100 = 1
Summary:
The coordinates of the foci and vertices are (0, ± 5√3), (0, ± 10) respectively. The length of the major axis, minor axis, and latus rectum are 20, 10, 5 respectively
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