# Find the equation of the circle with centre (- 2, 3) and radius 4

**Solution:**

The equation of a circle with centre(h, k) and radius r is given as

(x - h)^{2} + (y - k)^{2} = r^{2}

It is given that centre (h, k) = (- 2, 3)

and radius (r ) = 4.

Therefore,

the equation of the circle is

(x + 2)^{2} + (y - 3)^{2} = 4^{2}

x^{2} + 4x + 4 + y^{2} - 6y + 9 = 16

x^{2} + y^{2} + 4x - 6y - 3 = 0

NCERT Solutions Class 11 Maths Chapter 11 Exercise 11.1 Question 2

## Find the equation of the circle with centre (- 2, 3) and radius 4

**Summary:**

The equation of the circle is x^{2} + y^{2} + 4x - 6y - 3 = 0

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