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# Find the equation of the line perpendicular to the line x - 7 y + 5 = 0 and having x intercept 3

**Solution:**

The given equation of the line is x - 7 y + 5 = 0

Or y = 1/7 x + 5/7, which is of the form y = mx + c

Therefore, slope of the given line is 1/7

The slope of the line perpendicular to the line having a slope is m = 1/(1/7) = - 7

The equation of the line with slope - 7 and x-intercept 3 is given by

y = m (x - d)

y = -7 (x - 3)

y = - 7x + 21

y + 7x = 21

Hence, the required equation of the line is y + 7x = 21

NCERT Solutions Class 11 Maths Chapter 10 Exercise 10.3 Question 8

## Find the equation of the line perpendicular to the line x - 7 y + 5 = 0 and having x intercept 3

**Summary:**

The equation of the line perpendicular to the line x - 7 y + 5 = 0 and having x intercept 3 is y + 7x = 21

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