# If 123123A4 is divisible by 11, find the value of A.

**Solution:**

If the __number__ 123123A4 is divisible by 11 then the difference of the __sum__ of digits in odd places and even places is 0 or multiple of 11.

Therefore:

(1 + 3 + 2 + A) - (2 + 1 + 3 + 4) = 0

A = 4

Or

(1 + 3 + 2 + A) - (2 + 1 + 3 + 4) = 11

6 + A - 10 = 11

A = 15 which is not a valid option because it is two digit.

Hence if A = 4 the number 123123A4 is divisible by 11.

**✦ Try This: **If 456456A7 is divisible by 11, find the value of A.

If the number 456456A7 is divisible by 11 then the difference of the sum of digits in odd places and even places is 0 or multiple of 11

Therefore:

(4 + 6 + 5 + A) - (5 + 4 + 6 + 7) = 0

A = 7

Or

(4 + 6 + 5 + A) - (5 + 4 + 6 + 7) = 11

A = 18

A = 18 which is not a valid option because it is two digit.

Hence if A = 7 the number 456456A7 is divisible by 11.

**☛ Also Check: **NCERT Solutions for Class 8 Maths Chapter 16

**NCERT Exemplar Class 8 Maths Chapter 13 Problem 73**

## If 123123A4 is divisible by 11, find the value of A.

**Summary:**

If A = 4 the number 123123A4 is divisible by 11.

**☛ Related Questions:**

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