# In Fig. 8.13, find tan P – cot R

**Solution:**

We use the basic formula for tan and cot to solve the question.

Now, here, we have hypotenuse PR = 13 cm, and side PQ = 12 cm.

Now, from the pythagoras theorem, we have PQ^{2} + QR^{2} = PR^{2}

So, we have QR = √(PR^{2} - QR^{2}) = √(13^{2} - 12^{2}) = √25 = 5 cm.

Hence, we have cot R = QR/PQ = 5/12.

Also, tan P = QR/PQ = 5/12.

So, tan P - cot R = 5/12 - 5/12 = 0

**Video Solution:**

## In Fig. 8.13, find tan P – cot R

### Maths NCERT Solutions Class 10 - Chapter 8 Exercise 8.1 Question 2:

In Fig. 8.13, find tan P – cot R

tan P - cot R = 5/12 - 5/12 = 0