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# Mrs. Kaushik has a square plot with the measurement as shown in the figure. She wants to construct a house in the middle of the plot. A garden is developed around the house. Find the total cost of developing a garden around the house at the rate of ₹ 55 per m².

**Solution:**

The plot is square from the outside while the area of the house to be constructed is rectangular in the middle of the plot. From the diagram, we can see that the area of the garden is the difference between the area of the square plot and the area of the house.

Area of the square plot = side × side = 25 m × 25 m = 625 m²

Area of the house = length × breadth = 15 m × 20 m = 300 m²

Area of the garden to be developed = (Area of the square plot) - (Area of the house) = 625 m² - 300 m² = 325 m²

Hence, Area of the garden to be developed = 325 m²

The cost of developing a garden around the house = Rs 55 per m²

Therefore, the total cost of developing a garden of area 325 m² = 325 × 55 = Rs 17,875

**☛ Check: **NCERT Solutions for Class 8 Maths Chapter 11

**Video Solution:**

## Mrs. Kaushik has a square plot with the measurement as shown in the figure. She wants to construct a house in the middle of the plot. A garden is developed around the house. Find the total cost of developing a garden around the house at the rate of ₹ 55 per m².

Class 8 Maths NCERT Solutions Chapter 11 Exercise 11.1 Question 2

**Summary:**

Mrs. Kaushik has a square plot with the measurement as shown in the figure. She wants to construct a house in the middle of the plot. A garden is developed around the house. The total cost of developing a garden around the house at the rate of ₹ 55 per m² is ₹ 17,875.

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