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# Solve 3x + 8 > 2 , when

(i) x is an integer (ii) x is a real number

**Solution:**

The given inequality is 3x + 8 > 2

3x + 8 > 2

⇒ 3x + 8 - 8 > 2 - 8

⇒ 3x > - 6

⇒ 3x/3 > - 6/3

⇒ x > - 2

**(i)** The integers greater than - 2 are - 1, 0, 1, 2, ....

Thus, when x is an integer, the solutions of the given inequality are - 1, 0, 1, 2...

Hence, in this case, the solution set is {- 1, 0, 1, 2,....}

**(ii)** When x is a real number, the solutions of the given of the inequality are all the real numbers, which are greater than - 2

Thus, in this case, the solution set is (- 2, ∞)

NCERT Solutions Class 11 Maths Chapter 6 Exercise 6.1 Question 4

## Solve 3x + 8 > 2 , when (i) x is an integer (ii) x is a real number

**Summary:**

A linear inequation 3x + 8 > 2 is given. We have found that in this case the solution set is (- 2, ∞)

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