The curved surface area of a cylinder is reduced by ____________ per cent if the height is half of the original height.
Solution:
The curved surface of a cylinder = 2πrh
Where r = radius of the cylinder
And h = height of the cylinder
If the height is reduced by half i.e. it becomes h/2 then the curved surface area of a cylinder becomes:
New Surface Area of cylinder = 2πr(h/2) = πrh
Decrease in surface area = 2πrh - πrh = πrh
Percentage decrease in surface Area = [(2πrh - πrh)/2πrh] × 100 = 50%
✦ Try This: The curved surface area of a cylinder is reduced by ____________ per cent if the radius is reduced to half of the original radius and height remains constant.
The curved surface of a cylinder = 2πrh
Where r = radius of the cylinder
And h = height of the cylinder
If the radius is reduced by half i.e. it becomes r/2 then the curved surface area of a cylinder becomes:
New Surface Area of cylinder = 2π(r/2)(h) = πrh
Decrease in surface area = 2πrh - πrh = πrh
Percentage decrease in surface Area = [(2πrh - πrh)/2πrh] × 100 = 50%
☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 11
NCERT Exemplar Class 8 Maths Chapter 11 Problem 35
The curved surface area of a cylinder is reduced by ____________ per cent if the height is half of the original height.
Summary:
The curved surface area of a cylinder is reduced by fifty per cent if the height is half of the original height
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