# The value of p for 51² - 49² = 100p is 2. Is the given statement true or false

**Solution:**

The statement ‘The value of p for 51² - 49² = 100p is 2’ is true.

Given, 51² - 49² = 100p

51² - 49²

Using standard identity : a^{2} - b^{2} = (a + b) (a - b)

Here, a = 51 and b = 49,

51² - 49² = 100 p

(51 + 49) (51 - 49) = 100 p

100 × 2 = 100 p

200 = 100 p

p = 2

**✦ Try This: **State true or false: The value of ‘t’ for 271² - 29² = 24200t is 3

The statement The value of ‘t’ for 271² - 29² = 24200t is 3 is true

Given, 271² - 29² = 24200t

We have the identity: a² - b² = (a - b) (a + b)

Here a = 271 and b = 29

∴ 271² - 29² = (271 - 29) (271 + 29)

= 242 × 300

= 24200 × 3

∴ t = 3

**☛ Also Check: **NCERT Solutions for Class 8 Maths Chapter 9

**NCERT Exemplar Class 8 Maths Chapter 7 Problem 78**

## The value of p for 51² - 49² = 100p is 2. Is the given statement true or false

**Summary: **

The statement ‘The value of p for 51² - 49² = 100p is 2’ is true

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