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# To construct a triangle similar to a given ∆ABC with its sides 3/7 of the corresponding sides of ∆ABC, first draw a ray BX such that ∠CBX is an acute angle and X lies on the opposite side of A with respect to BC. Then locate points B_{1} , B_{2} , B_{3} , ... on BX at equal distances and next step is to join

a. B_{10 }to C

b. B_{3 }to C

c. B_{7 }to C

d. B_{4 }to C

**Solution:**

In order to construct a __triangle__ similar to a given ∆ABC with its sides 3/7 we have to divide BC in the ratio 3 : 7

BX should have 7 equidistant points on it as 7 is a greater number

Now we have to join B_{7} to C.

Therefore, the next step is to join B_{7} to C.

**✦ Try This: **To construct a triangle similar to a given ∆ABC with its sides 5/9 of the corresponding sides of ∆ABC, first draw a ray BX such that ∠CBX is an acute angle and X lies on the opposite side of A with respect to BC. Then locate points B_{1}, B_{2}, B_{3}, ... on BX at equal distances and next step is to join

**☛ Also Check:** NCERT Solutions for Class 10 Maths Chapter 11

**NCERT Exemplar Class 10 Maths Exercise 10.1 Problem 4**

## To construct a triangle similar to a given ∆ABC with its sides 3/7 of the corresponding sides of ∆ABC, first draw a ray BX such that ∠CBX is an acute angle and X lies on the opposite side of A with respect to BC. Then locate points B_{1} , B_{2} , B_{3} , ... on BX at equal distances and next step is to join a. B_{10} to C, b. B_{3} to C, c. B_{7} to C, d. B_{4} to C

**Summary:**

To construct a triangle similar to a given ∆ABC with its sides 3/7 of the corresponding sides of ∆ABC, first draw a ray BX such that ∠CBX is an acute angle and X lies on the opposite side of A with respect to BC. Then locate points B_{1} , B_{2} , B_{3} , ... on BX at equal distances and the next step is to join B_{7} to C

**☛ Related Questions:**

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- By geometrical construction, it is possible to divide a line segment in the ratio 2 + √3: 2 - √3. Wr . . . .

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