LCM of 12, 15, 20, and 27
LCM of 12, 15, 20, and 27 is the smallest number among all common multiples of 12, 15, 20, and 27. The first few multiples of 12, 15, 20, and 27 are (12, 24, 36, 48, 60 . . .), (15, 30, 45, 60, 75 . . .), (20, 40, 60, 80, 100 . . .), and (27, 54, 81, 108, 135 . . .) respectively. There are 3 commonly used methods to find LCM of 12, 15, 20, 27  by listing multiples, by prime factorization, and by division method.
1.  LCM of 12, 15, 20, and 27 
2.  List of Methods 
3.  Solved Examples 
4.  FAQs 
What is the LCM of 12, 15, 20, and 27?
Answer: LCM of 12, 15, 20, and 27 is 540.
Explanation:
The LCM of four nonzero integers, a(12), b(15), c(20), and d(27), is the smallest positive integer m(540) that is divisible by a(12), b(15), c(20), and d(27) without any remainder.
Methods to Find LCM of 12, 15, 20, and 27
The methods to find the LCM of 12, 15, 20, and 27 are explained below.
 By Listing Multiples
 By Prime Factorization Method
 By Division Method
LCM of 12, 15, 20, and 27 by Listing Multiples
To calculate the LCM of 12, 15, 20, 27 by listing out the common multiples, we can follow the given below steps:
 Step 1: List a few multiples of 12 (12, 24, 36, 48, 60 . . .), 15 (15, 30, 45, 60, 75 . . .), 20 (20, 40, 60, 80, 100 . . .), and 27 (27, 54, 81, 108, 135 . . .).
 Step 2: The common multiples from the multiples of 12, 15, 20, and 27 are 540, 1080, . . .
 Step 3: The smallest common multiple of 12, 15, 20, and 27 is 540.
∴ The least common multiple of 12, 15, 20, and 27 = 540.
LCM of 12, 15, 20, and 27 by Prime Factorization
Prime factorization of 12, 15, 20, and 27 is (2 × 2 × 3) = 2^{2} × 3^{1}, (3 × 5) = 3^{1} × 5^{1}, (2 × 2 × 5) = 2^{2} × 5^{1}, and (3 × 3 × 3) = 3^{3} respectively. LCM of 12, 15, 20, and 27 can be obtained by multiplying prime factors raised to their respective highest power, i.e. 2^{2} × 3^{3} × 5^{1} = 540.
Hence, the LCM of 12, 15, 20, and 27 by prime factorization is 540.
LCM of 12, 15, 20, and 27 by Division Method
To calculate the LCM of 12, 15, 20, and 27 by the division method, we will divide the numbers(12, 15, 20, 27) by their prime factors (preferably common). The product of these divisors gives the LCM of 12, 15, 20, and 27.
 Step 1: Find the smallest prime number that is a factor of at least one of the numbers, 12, 15, 20, and 27. Write this prime number(2) on the left of the given numbers(12, 15, 20, and 27), separated as per the ladder arrangement.
 Step 2: If any of the given numbers (12, 15, 20, 27) is a multiple of 2, divide it by 2 and write the quotient below it. Bring down any number that is not divisible by the prime number.
 Step 3: Continue the steps until only 1s are left in the last row.
The LCM of 12, 15, 20, and 27 is the product of all prime numbers on the left, i.e. LCM(12, 15, 20, 27) by division method = 2 × 2 × 3 × 3 × 3 × 5 = 540.
ā Also Check:
 LCM of 48 and 60  240
 LCM of 72 and 24  72
 LCM of 24 and 27  216
 LCM of 17 and 19  323
 LCM of 16, 24 and 36  144
 LCM of 207 and 138  414
 LCM of 10 and 25  50
LCM of 12, 15, 20, and 27 Examples

Example 1: Which of the following is the LCM of 12, 15, 20, 27? 21, 540, 120, 52.
Solution:
The value of LCM of 12, 15, 20, and 27 is the smallest common multiple of 12, 15, 20, and 27. The number satisfying the given condition is 540. ∴LCM(12, 15, 20, 27) = 540.

Example 2: Find the smallest number that is divisible by 12, 15, 20, 27 exactly.
Solution:
The value of LCM(12, 15, 20, 27) will be the smallest number that is exactly divisible by 12, 15, 20, and 27.
⇒ Multiples of 12, 15, 20, and 27: Multiples of 12 = 12, 24, 36, 48, 60, 72, 84, 96, 108, 120, . . . ., 504, 516, 528, 540, . . . .
 Multiples of 15 = 15, 30, 45, 60, 75, 90, 105, 120, 135, 150, . . . ., 495, 510, 525, 540, . . . .
 Multiples of 20 = 20, 40, 60, 80, 100, 120, 140, 160, 180, 200, . . . ., 500, 520, 540, . . . .
 Multiples of 27 = 27, 54, 81, 108, 135, 162, 189, 216, 243, 270, . . . ., 459, 486, 513, 540, . . . .
Therefore, the LCM of 12, 15, 20, and 27 is 540.

Example 3: Find the smallest number which when divided by 12, 15, 20, and 27 leaves 2 as the remainder in each case.
Solution:
The smallest number exactly divisible by 12, 15, 20, and 27 = LCM(12, 15, 20, 27) ⇒ Smallest number which leaves 2 as remainder when divided by 12, 15, 20, and 27 = LCM(12, 15, 20, 27) + 2
 12 = 2^{2} × 3^{1}
 15 = 3^{1} × 5^{1}
 20 = 2^{2} × 5^{1}
 27 = 3^{3}
LCM(12, 15, 20, 27) = 2^{2} × 3^{3} × 5^{1} = 540
⇒ The required number = 540 + 2 = 542.
FAQs on LCM of 12, 15, 20, and 27
What is the LCM of 12, 15, 20, and 27?
The LCM of 12, 15, 20, and 27 is 540. To find the LCM of 12, 15, 20, and 27, we need to find the multiples of 12, 15, 20, and 27 (multiples of 12 = 12, 24, 36, 48 . . . . 540 . . . . ; multiples of 15 = 15, 30, 45, 60 . . . . 540 . . . . ; multiples of 20 = 20, 40, 60, 80 . . . . 540 . . . . ; multiples of 27 = 27, 54, 81, 108 . . . . 540 . . . . ) and choose the smallest multiple that is exactly divisible by 12, 15, 20, and 27, i.e., 540.
How to Find the LCM of 12, 15, 20, and 27 by Prime Factorization?
To find the LCM of 12, 15, 20, and 27 using prime factorization, we will find the prime factors, (12 = 2^{2} × 3^{1}), (15 = 3^{1} × 5^{1}), (20 = 2^{2} × 5^{1}), and (27 = 3^{3}). LCM of 12, 15, 20, and 27 is the product of prime factors raised to their respective highest exponent among the numbers 12, 15, 20, and 27.
⇒ LCM of 12, 15, 20, 27 = 2^{2} × 3^{3} × 5^{1} = 540.
Which of the following is the LCM of 12, 15, 20, and 27? 540, 25, 52, 27
The value of LCM of 12, 15, 20, 27 is the smallest common multiple of 12, 15, 20, and 27. The number satisfying the given condition is 540.
What are the Methods to Find LCM of 12, 15, 20, 27?
The commonly used methods to find the LCM of 12, 15, 20, 27 are:
 Prime Factorization Method
 Division Method
 Listing Multiples
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